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Solution (a) If f(x;y;z)=x2 y2 z2 then a normal of the surface x2 y2 z2 =9at(2;2;1) is given by the gradient rf(x;y;z)j (2;2;1) =(2xi2yj2zk)jfx=2;y=2;z=1g=4i4j2k Actually we will take the normal to be n =2i2jkThe extra factor 2 is not needed Thus the equation of the tangent plane to. # ' ( ) ' ( * ' ' ( , & " !. Z z ¯° ± !.

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