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. Scicario Day of the Soldado X B J I F f C E I u E U E \ _ h 15 N ́uScicario v ̑ ҁB L V R g D ̊ g 債 A e X g č ɑ 荞 ނ悤 ɂȂ ߁A bIA ̓} b g E O C o ɓ v B O C o ͑O l ɗ 񂾃R r A l ̃A n h Ƒg ݁A g D m ̍R N v B g D ̌ ߂̖ U A ̑g D ̎d ƂɌ 悤 Ƃ 邪 A Z B } b g ɗU E Ɩ ꂽ A n h ͂ ۂ ͖ B. Given f (x) = 3x 2 – x 4, find the simplified form of the following expression, and evaluate at h = 0 This isn't really a functionsoperations question, but something like this often arises in the functionsoperations context This looks much worse than it is, as long as I'm willing to take the time and be careful.

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J Ó C x g s e J Ïꏊ ₢ \ { ԑ s ԑ ̓ Y i g H H A V N ȊC Y A _ Y ̔̔ B. R Ɏg 鍂 ׂ̃t ʐ^ f ޏW ł B 10,000 ̐ E ő勉 ̖ 摜 A ʐ^ T C g B u O HP A C X g ɂ p B p p A H ܂߂ăt i j ł BNo 1973 v C x g r ` ̗. ´_”ƒ}{è©C´‰ë`Cá’¦(ò6Oe·çn f“D JU³d¢œ 5 žA”_$°x?æä¡G "Ó ÛÁBŠç wøÓ‹ j ˆ%˜F Kº¦Ø FNË)‹/C'*~gÿg²}®hÁ ’h¤?ÉÍå”p ã0ê¹9A÷¾{öéS÷Ùy†Vz¯7ö@uw« = w‘ ƒã ^ °¶’íE'Û6Zßo;ÁÏ% ÑNIüö ÍÐ3šoïóƒ& &dØ=•ßL4‚Ò ä\Ý´a é&›ÂÏT }¬I4q 2¸@UÄå Ú.

{ f R A e B X g ́A f R A g ̕ y Ɛ Z p ̔ W A ړI Ƃ A f R A g Ɋ֘A Ƃ𒆐S Ƃ Đݗ ꂽ c ̂ł B u f R A e B X g v Ƃ́A f R d E f R O b Y ɑ \ 郉 C X g Ȃǂ g p f R V Z @ g f R A g h ̐ Z p ҂ w ܂ B. Suppose you are given the two functions f (x) = 2x 3 and g(x) = –x 2 5Composition means that you can plug g(x) into f (x)This is written as "(f o g)(x)", which is pronounced as "fcomposeg of x"And "( f o g)(x)" means "f (g(x))"That is, you plug something in for x, then you plug that value into g, simplify, and then plug the result into f. A For f(g(x) you take the f(x) equation, except, instead of the "x"s, you put in the "g(x)" equation Like this f(g(x)= 3(2x6) (then you multiply the 3 to the 2x6 and get) f(g(x)= 6x18 And that is your final answer For g(f(x) you do the exact reverse You start with the "g(x)" function, and then instead of the x, you stick in the f(x.

䌧 s t ̃G X e T E G X e X N E v C x g T E Y @La cherir New 点 N V ^ R i E B X ̊ g h ~ ̂ ߂̋x Ɨv ɔ 25 ( y) `5 6 ( ) ܂ł̊ Ԃ x ݂ Ă ܂ B. Solved Consider the following two functions f(x) and g(x) f(x) = 4 x^2;. > 8 G 0 B ;.

R r î ì ì î v r r } v x ò x I E C I F 3 ;. H 8 H 5 H 0 F H 8 E 5 @ E H 8 E 0 F 0 G > 5 I 8 õ X ì ì r í ì X ì ì C E 4 r r 5 v r r 4 r } s. Let f(x) = x2 and g(x) = −x3 x2 3x 2 Then f(−1) = g(−1) and f(2) = g(2) Using Rolle’s Theorem, show that there is at least one value c in the interval (−1, 2) where the tangent line to f at (c, f(c)) is parallel to the tangent line to g at (c, g(c)).

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G b v y W uWhat's new v ɂču J u ̏Љ Ă ܂ B Y w A g ȊO ̏ f ڂ Ă ܂ B ّ w C x g E j X. Author christopherdinardo Created Date 11/19/ AM. N X Y V N A H p e B A ̓񎟉 ȂǁA e p e B C x g 𕝍L Ă ܂ B l R O x ܂ł p ܂ B e ₨ ݕ A \ Z ȂǁA q l ̂ Ƀt L V u ɑΉ Ă ܂ ̂ŁA C y ɂ k B.

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Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history. M417 Homework 3 Solutions Spring 04 (1) (a) For any subsets C 1,C 2 ⊂ A, show that f(C 1 ∪ C 2) = f(C 1) ∪ f(C 2) We must show that any element of f(C 1 ∪ C 2) is an element of f(C 1) ∪ f(C 2), and vice versaSo let y ∈ f(C 1 ∪ C 2) Then y = f(x) for some x ∈ C 1 ∪ C 2If x ∈ C.